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Find dy/dx if y=(x-1)/sin x?
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To determine dy/dx, we'll have to use the quotient rule:
(f/g)' = (f'*g - f*g')/`g^(2)`
Let f(x) = x-1 => f'(x) = 1
Let g(x) = sin x => g'(x) = cos x
dy/dx = [sin x - (x-1)*cos x]/`sin^(2)` x
Therefore, the requested first derivative of the given function is: dy/dx = (sin x + cos x - x*cos x)/`sin^(2)` x.
Posted by giorgiana1976 on August 15, 2011 at 11:06 PM (Answer #1)
let (x-1)=u, sinx=v
Posted by kimanijuniour on March 2, 2012 at 8:27 PM (Answer #2)
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