# Find `dy/dx` given that `x=3/t` and `y=sqrt(t)*e^(-t)`

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The expression in terms of t for x is `x = 3/t` and for y it is `y = e^(-t)*sqrt t`

`dy/dt = -e^(-t)*sqrt t + e^(-t)*(1/(2*sqrt t))`

`dx/dt = -3/t^2`

`dy/dx = (dy/dt)/(dx/dt)` = `(-e^(-t)*sqrt t + e^(-t)*(1/(2*sqrt t)))/(-3/t^2)` ` `

= `(t^2*e^(-t)(2*t - 1))/(6*sqrt t)`

= `(t^2*e^(-t)(2*t - 1))/(6*sqrt t)`` `

**The derivative `dy/dx = (t^2*e^(-t)(2*t - 1))/(6*sqrt t)`**