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Find dy/dx, when x = 3at^2 , y = 2at^6
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The derivative `dy/dx` has to be determined given that `x = 3at^2` , `y = 2at^6`
`x = 3at^2`
=> `dx/(dt) = 6at`
`y = 2at^6`
=> `dy/(dt) = 12at^5`
`dy/dx = (dy/(dt))/(dx/(dt))`
=> `dy/dx = (12at^5)/(6at) `
The derivative `dy/dx = 2*t^4`
Posted by justaguide on November 30, 2012 at 12:58 PM (Answer #1)
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