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Find dy/dx by implicit differentiation. y cos x = 2x^2 + 4y^2
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The derivative `dy/dx` of y*cos x = 2x^2 + 4y^2 has to be determined.
Using implicit differentiation
`y*(-sin x) + (dy/dx)*cos x= 4x + 8y*(dy/dx)`
=> `(dy/dx)(cos x - 8y) = 4x + y*sin x`
=>` dy/dx = (4x + y*sin x)/(cos x - 8y)`
The derivative `dy/dx` of `y*cosx =2x^2 +4y^2` is `dy/dx = (4x + y*sin x)/(cos x - 8y)`
Posted by justaguide on March 7, 2012 at 8:30 AM (Answer #1)
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