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Find the distance from the point (-5,6) to the origin.

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jolenta | Student, College Freshman | (Level 1) Honors

Posted November 30, 2010 at 7:31 PM via web

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Find the distance from the point (-5,6) to the origin.

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giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted November 30, 2010 at 7:33 PM (Answer #1)

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We'll form a right angle triangle, whose hypotenuse is the distance from origin to the point and one cathetus is its abscisa and the other cathetus is the ordinate.

We'll note the distance as r:

r = ? units.

We'll note the abscisa as x:

x = -5 units

x^2 = 25 square units

We'll note the ordinate as y:

y = 6 units

y^2 = 36 units

We'll calculate r using Pythagorean Theorem:

r^2 = x^2 + y^2

r^2 = 25 + 36

r^2 = 61

r = sqrt 61

r = 7.81 units approx

We'll reject the negative solution since the distance is always positive

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neela | High School Teacher | (Level 3) Valedictorian

Posted November 30, 2010 at 10:19 PM (Answer #2)

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To find the distance of the point (-5, 6) from the origin .

We know that the distance d between the two points (x1,y1P and (x2,y2) is given by:

d = sqrt{(x2-x1)^2 +(y2-y1)^2}.

Therefore the distance between (-5, 6) and the origin (0,0) is given by:

d = sqrt{(0- -(5))^2+((0-6)^2} .

d = sqrt{25+36}.

d = sqrt (61}.

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