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find the distance between A(2,4) and the line 2x-3y + 5 = 0
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High School Teacher
d: 2x-3y + 5 =0
The distance between a point and line formula is:
d = l (ax1 + by1 + c l/ sqrt(a^2 + b^2)
= l (2*2 + 4*-3 + 5 l / sqrt(4 + 9)
= l -3l / sqrt(13)
Then the distance is 3/sqrt13 units.
Posted by hala718 on August 5, 2010 at 8:41 AM (Answer #1)
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