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find the derivative of the transcendal function. y=`sec x/x`
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High School Teacher
Derivation of quotient:
`(f/g)'=(f' cdot g-f cdot g')/(g^2)` (1)
`(sec x)'=(1/cos x)'=sin x/(cos^2 x)=secx tanx` (2)
Also as you probably know `x'=1`.
Now by using rule for derivation of quotient (1) and knowing how to derivate `sec x` (2) we get
`(sec x/x)'=(sec x tan x cdot x-sec x)/(x^2)` <-- Solution
Posted by tiburtius on February 20, 2013 at 7:22 PM (Answer #1)
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