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Find the derivative of the function.y= 1/(x^4+3)^3  ............y=1 divided by x to...

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frdsmith | Student, Grade 11 | eNoter

Posted March 6, 2012 at 7:01 AM via web

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Find the derivative of the function.

y= 1/(x^4+3)^3  ............y=1 divided by x to the power of 4 plus 3 all in the paratheses and all of the bottom half is to the 3rd power

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hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted March 6, 2012 at 7:07 AM (Answer #1)

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`y= 1/(x^4+3)^3 `

`==gt y= (x^4 + 3)^-3 `

`==gt y'= -3(x^3+3)' (x^4 +3)^-4 `

`==gt y'= -3(3x^2)(x^4+3)^-4 `

`==gt y'= (-9x^2)/(x^4+3)^4`

 

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