# Find the derivative of the function g(t)= `3/(sqrt(t))`

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The function g(t)= `3/(sqrt(t))` = `3*t^(-1/2)`

The derivative of g(t) is `3*(-1/2)*t^(-1/2 - 1)`

=> `(-3/2)*t^(-3/2)`

**The required derivative is g'(t) = `(-1.5)/t^1.5` **

with steps: Find the derivative of the function g(t)= 3/sqrt(t)

g(t)= = 3 t^(-1/2)

g'(t)=3(-1/2)t^(-1/2 - 1)

g'(t)=-3/2 t^(-3/2)