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Find the components of 82 N∠139°.a.(-61.9 N, 53.8 N) b.(53.8 N, 61.9 N) c.(-53.8 N,...
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The force is 82 N.
The direction is with a angle of 139 deg.
Let us assume that the angle is measured from the x-axis to the counter clockwise direction. Then the force is having an angle 49 deg to the anti clock wise direction of y axis.
Then the force is at the second quarter of the x-y plane that y is positive and x is negative.
The component of force to y direction = 82 cos 49 = 53.8 N
The component of force to -x direction = 82 sin 49 = 61.9 N
So the answer is (-61.9,53.8). The correct answer is (a)
Posted by jeew-m on July 31, 2012 at 2:07 AM (Answer #1)
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