Find the coefficient of kinetic friction.
A dock worker loading crates on a ship finds that a 15kg crate, initially at rest on a horizontal surface, requires a 64N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 57N is required to keep it moving with a constant speed.
The acceleration of gravity is 9.8 m/s^2.
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Kinetic friction is the maximum force required to maintain the uniform motion or maintain the constant velocity. Under such condition , the net force due to the kinetic frictional force and the exerted force is zero.
The kinetic frictional force = Mk * mg, where Mk is the coeefficient of kinetic friction between the crate and the horizontal surface.m is the mass of the crate and g is the acceleration due to gravity.
Applied force =57 N,
Therefore, the net force = 0.
Mk*(15*g N)+57N=0 Therefore, Mk= -57N/(15*9.8)N = -0.3878 or the coefficient of friction is 0.3878.
Mass of crate = m = 15 kg
Force required to set the crate in motion = f1 = 64 N
Force required to keep the crate in moving at constant speed = f2 = 57 N
Acceleration of gravity = g = 9.8 m/s^2
Coefficient of kinetic friction =
(Force required to keep the crate in moving at constant speed)/(Perpendicular force exerted on the crate)
Perpendicular force exerted on the crate = m*g
Substituting given value of m and g we get:
Perpendicular force exerted on the crate =15*9.8 = 147 N
Substituting this value of perpendicular force and Force required to keep the crate in moving at constant speed in equation for coefficient of kinetic friction we get:
Coefficient of kinetic friction = 57/147 = 0.3878
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