find the area of a triangle with:

m<B=128°

a=16

c=24

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We are asked to find the area of a triangle with the m<B =128 degrees, a = 16, and c = 24.

Since we have been given two sides and the included angle, we will use the following formula:

Area = 1/2ac(sinB)

Area = 1/2(16)(24)sin128

Area = 151.30 square units

**The area of the triangle is 151.30 square units.**

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