find the area of the parallelogram spanned by vectors given, pls alo verify answer

6**i**+3**j** and 6**i**-3**j**

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Let

`u=6i+3j+0k`

`v=6i-3j+0k`

Where i,j, and k are mutually orthogonal triod.

area of parallelogram spanned by vectors u and v is magnitude of vector u x v .

Thus

`uxxv=|[i,j,k],[6,3,0],[6,-3,0]|`

`=k(-18-18)=-36k`

Thus magnitude of u x v is

`|uxxv|=sqrt((-36)^2)`

`=36` sq.unit

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