find the area function A(x) for the functiony=2t+1 with a=0. please include graph with solution



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Posted on (Answer #1)

By fundamental theorem of integral calculus ,the area function is



`` But we have

`int(2t+1)dt=t^2+t+c`    ,where c is constant to be determined under given condition a=0

Thus we have  (we assume point has zero area)

so  put


`c=0`   (when you put t=0)

Thus area function is



Thus area function is


and its graph is


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