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We need to determine the area of the circle whose circumference is 34pi.
We know that the area of the circle is:
a = r^2 n pi where r is the radius.
Then we need to determine the radius.
Given that the circumference = 34pi.
==> C = 2* pi * r = 34*pi
We will divide by 2*pi.
==> r= 34pi/ 2pi
==> r= 17
Then the radius of the circle = 17 unit.
Now we will substitute into the area.
a = r^2 *pi = 17^2 * pi = 289pi = 907.92 square units.
Then, the area of the circle is 907.92 square units.
To find the area of the circle whose circumference = 34pi.
We know that the relation between the circimference C and the radius r is given by: C = 2pir.
C = 34pi by data.
Therefore 2pir = 34pi. S = r = 34pi/2pi = 17.
We are A of the circle is given by A = pir^2.
Therefore A = Pi*17^2 = (3.14159)289 = 907.92 sq units.
Therefore the area of the given circle A = 907.92 sq units.
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