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The slope of the line tangent to a curve g(x) at any point x is equal to g'(x).
For the function y = g(x). At the point x = 2, g'(2) = 5 and g(2) = -6
The slope of the tangent is 5 and it passes through the point (2, -6) This gives the slope of the line as (y + 6)/(x - 2) = 5
=> y + 6 = 5x - 10
=> 5x - y - 16 = 0
The required equation of the tangent is 5x - y - 16 = 0
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