# Find an equation in standard form of the line containing point P and having slope m. P(2,3),m=1

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The standard format of a straight line is y = mx+c

m is the slope and c is the y intercept.

So if our line is y = mx+b then it passes through point P (2,3).

When m = 1

3 = 1*2+b

b = 1

*So the equation of line is y = x+1*

When m = -1

3 = -1*2+b

b = 5

*So the equation of line is y = -x+5*

When b = 2

3 = m*2+2

m = 1/2

*So the equation of line is y = (1/2)x+2*

**Sources:**

P and having slope m. P(2,3),m=1

Standard form is actually Ax + By + C where A, B, and C are integer coefficients.

Given a point and its slope, its best to use the point slope form which in general terms is y - y1 = m(x - x1) where (x1,y1) is the point and m is the slope.

You can use that to get to standard.

y - 3 = 1(x - 2)

Rearrange to get x and y on the same side:

y - x = 1