Find algerbracically the modulus and the argrument of the complex number `(-1+iota)^3/(1+iota)^4` `` ` `



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Posted on (Answer #1)

`((-1+i)^3)/((1+i)^4)`   Expand the binomials:


Simplify using `i=i,i^2=-1,i^3=-i,i^4=1` :



So `z=((-1+i)^3)/((1+i)^4)=-1/2-1/2i`

The modulus of `z=a+bi` is `|z|=sqrt(a^2+b^2)` so


To find the argument we need the reference angle: `theta=tan^(-1)(b/a)` so `theta=tan^(-1)(1)=45^@`

Since a,b<0 the angle is in the third quadrant. Thus `arg(z)=225^@`





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