f(x) = x^4 + x^3 - 3x^2 - 7x - 4 Find this root and then use the calculator to determine any other irrational roots (rounded to 3 decimals).  Enter answers from smallest to largest.



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aruv's profile pic

Posted on (Answer #1)


Apply remainder theorem to factorize f(x).

f(-1)=0 this implies x+1 is factor of f(x)




we can solve


we will get

x=2.1958,-1.0979+0.785 i,-1.0979-0.785i

Thus zeros of f(x) are

x=-1,2.196,-1.098+0.785i,-1.098-0.785i ,

two zeros are real and two are complex conjugate.

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