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`f(x) = x^2 `     f(x) - vertex (0,0), goes thru points (2,4), (-2,4)   g(x) -...

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kristenmarieb... | Student, Grade 10 | Valedictorian

Posted June 19, 2013 at 11:23 PM via web

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`f(x) = x^2 `    

f(x) - vertex (0,0), goes thru points (2,4), (-2,4)

 

g(x) - vertex (2, -6), goes thru points (3,-3), (4,6)

Which equation matches g(x)?

a)  `(3(x-2))^2 - 6`

b)`(1/3(x-2))^2 - 6`

c)  `(3(x+2))^2 - 6`

d)  `(1/3(x+2))^2 - 6`

e) `3(x+2)^2 - 6`

f)  `3(x-2)^2 - 6`

g)  `1/3(x+2)^2 - 6`

h)  `1/3(x-2)^2 - 6`

Tagged with algebra 2, math

1 Answer | Add Yours

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Mary Joy Ripalda | High School Teacher | (Level 3) Educator

Posted June 20, 2013 at 12:21 AM (Answer #1)

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To determine the equation of g(x), apply the vertex form of a parabola which is:

`y = a(x-h)^2+ k`

Then, plug-in the vertex of g(x).

`y = a(x-2)^2 - 6`

To determine the value of a, plug-in the other points of g(x). Use (3,-3).

`-3=a(3-2)^2-6`

`-3=a(1)^2-6`

`-3=a-6`

`-3+6=a-6+6`

`3=a`

Hence, `g(x) = 3(x-2)^2-6` .

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