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f(x)= (x^2 +10x +6)/(x+9)Given the rational function: (a) state the domain. (b) find...
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High School Teacher
`x+9!=0 => x!=-9`
Thus the domain is `(-oo,-9)U(-9,oo)`
The same value that is excluded from the domain will give you the vertical asymptote, thus x=-9 is vertical asymptote.
This function has no horizontal asymptote.
To obtain the oblique asymptote, we can perform the long devision this will give us `(x^2+10x+6)/(x+9)=x+1+(-3)/(x+9)`
Hence the oblique asymptote is y=x+1
Posted by rcmath on February 23, 2012 at 12:01 PM (Answer #1)
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