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f(x)= cos x/2+sin x ; f(x)= (2+sin x)(-sin x)-cos x cos x/`(2+sin x)^(2)` -- using the...
f(x)= cos x/2+sin x ;
f(x)= (2+sin x)(-sin x)-cos x cos x/`(2+sin x)^(2)`
-- using the tool of calculus, it can be shown that function f(x) given, the zeroes of f'(x) give the location of any maximum and/or minimum values. find the location of these values in the inteval [0,2 ], using trig identities as needed to solve f'(x) = 0
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High School Teacher
`f(x)= (1/2)cos(x)+sin(x) ` defined on [0,2],
For maxima / minima , find the derivative of f(x) with respect to x.
Thus genera solution is
if n=1 then `x!in[0,2]`
Thus minima/maxima lies in [0,2] if x=1.107 rad.
`f''(x)=-(1/2)cos(x)-sin(x) <0 `
Thus f(x) has maxima at x=1.107 rad.
Posted by aruv on July 11, 2013 at 2:11 AM (Answer #1)
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