# If `f(x)=3x^2` and g(x)=|2x-1| what is fog(-2)

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Given that:

`f(x)= 3x^2`

g(x)= l 2x-1 l

We need to find the value of fog(-2).

==> fog(-2)= f(g(-2))

==> g(-2)= l 2*-2 -1 l = l -5l = 54

==> fog(-2)= f(g(-2)) = f(5) = 3*`5^2` = 3*25 = 75

==> fog(-2) = 75