Better Students Ask More Questions.
f(x)= -2x^3-5x^2+7x+6 How would one find the x and y intercepts, intervals of...
1 Answer | add yours
High School Teacher
Evaluate the graph of `f(x)=-2x^3-5x^2+7x+6` :
We will need the first derivative:
(1) The y-intercept occurs when x=0 so the y-intercept is 6
(2) The x-intercepts occur when f(x)=0. Using a grapher the zeros are `x~~-3.287,-.640,1.427`
(3) The local extrema can be found using the first derivative. Extrema can only occur when `f'(x)=0` or fails to exist.
Using the quadratic formula the zeros of `f'(x)` are `x=-5/6+-sqrt(67)/6` or `x~~0.531,-2.198`
Using the first derivative test we find `x~~-2.198` to be a local minimum, and `x~~.0531` to be the local maximum.
(4) The end behavior of a polynomial is the end behavior of the leading term. Since the degree is 3 with a negative leading coefficient, `lim_(x->-oo)f(x)=oo,lim_(x->oo)f(x)=-oo`
Posted by embizze on February 24, 2013 at 5:29 PM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.