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If f'(x)=1/(7+cosx) what is f(x) ?
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To determine the primitive of the given function f'(x), we'll have to calculate the indefinite integral of f'(x).
Int f'(x)dx = Int dx/(7+cos x)
This is a trigonometric integral and we'll turn it into an integral of a rational function. We'll replace tan (x/2) by the variable t.
x/2 = arctan t
x = 2arctan t
We'll differentiate both sides:
dx = 2dt/(1 + t^2)
We'll write cos x = (1-t^2)/(1+t^2)
We'll re-write the integral in t:
Int dx/(7 + cos x) = Int [2dt/(1 + t^2)]/[7 + (1-t^2)/(1+t^2)]
Int [2dt/(1 + t^2)]/[(7 + 7t^2 + 1 - t^2)/(1+t^2)]
We'll simplify by (1 + t^2):
Int 2dt/(8 + 6t^2) = Int 2dt/2(4 + 3t^2)
Int 2dt/2(4 + 3t^2) = Int dt/3(4/3 + t^2)
Int dt/3(4/3 + t^2) = (1/3)*Int dt/[(2/sqrt3)^2 + t^2]
(1/3)*Int dt/[(2/sqrt3)^2 + t^2] = (1/3)*sqrt3/2*arctan (tsqrt3/2) + C
But the variable t is: t = tan x/2,
The primitive of the given function is f(x) = Int dx/(cosx + 7) = (sqrt3/6)*arctan [(tan x/2)*sqrt3/2] + C
Posted by giorgiana1976 on April 14, 2011 at 11:13 PM (Answer #1)
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