f(x) = -0.1x^2 + 3.2x - 3.5

graph the parabolla.

### 4 Answers | Add Yours

`-0.1x^2+3.2x-3.5=0`

`x^2-32x+35=0`

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Let f(x) represents y axis and x as usual x axis.

f(x) = -0.1x^2 + 3.2x - 3.5

`f(x)=y=-.1x^2+3.2x-3.5`

`y+3.5=-0.1(x^2-32x)`

`y+3.5=-0.1(x^2-32x+16^2)-0.1xx16^2`

`y+3.5+25.6=-0.1(x-16)^2`

`y+29.1=-0.1(x-16)^2`

Let y+29.1=Y

x-16=X origine is shifted to (16,-29.1)

Y=-0.1X^2

-10Y=X^2

This graph is in XY plane.

Please add this to my answer

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