Homework Help

f(x) = -0.1x^2 + 3.2x - 3.5 graph the parabolla.

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loishy | Student, Grade 10 | Salutatorian

Posted April 30, 2013 at 11:14 PM via web

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f(x) = -0.1x^2 + 3.2x - 3.5

graph the parabolla.

Tagged with graph the parabolla., math

4 Answers | Add Yours

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oldnick | Valedictorian

Posted April 30, 2013 at 11:28 PM (Answer #1)

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`-0.1x^2+3.2x-3.5=0`

`x^2-32x+35=0`

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oldnick | Valedictorian

Posted April 30, 2013 at 11:28 PM (Answer #2)

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pramodpandey | College Teacher | Valedictorian

Posted May 1, 2013 at 5:08 AM (Answer #3)

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Let  f(x) represents y  axis and x as usual x axis.

f(x) = -0.1x^2 + 3.2x - 3.5

`f(x)=y=-.1x^2+3.2x-3.5`

`y+3.5=-0.1(x^2-32x)`

`y+3.5=-0.1(x^2-32x+16^2)-0.1xx16^2`

`y+3.5+25.6=-0.1(x-16)^2`

`y+29.1=-0.1(x-16)^2`

Let  y+29.1=Y

x-16=X origine is shifted to  (16,-29.1)

Y=-0.1X^2

-10Y=X^2

This graph is in XY plane.

 

 

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pramodpandey | College Teacher | Valedictorian

Posted May 2, 2013 at 3:32 PM (Answer #4)

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Please add this to my answer

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