Express the roots of unity in standard for a+bi. Determine z and the four fourth roots of z if one fourth root of z is -2 - 2i.

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rcmath | High School Teacher | (Level 1) Associate Educator

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According to DeMoivre Theorem, the 4th root of a number


is given by `z_k=root(4)(r)(cos[(theta+2kPi)/4]+isin[(theta+2kPi)/4])`

Looking at the -2-2i=2(-1-i) this means that the sin and cos are equal, hence theta is either Pi/4 or Pi/4+Pi (1st and 3rd quadrant sin and cos have the same sign)
Since we both sin and cos are negative in the given problem then theta has to equal 5Pi.

`root(4)(r)[cos((5Pi)/4)+isin((5Pi)/4)]=-2-2i =>`

`root(4)(r)[-sqrt(2)/2-isqrt(2)/2]=-2-2i =>`

`root(4)(r)*sqrt(2)/2=2 =>`



Thus `z=64(cos5Pi+isin5Pi)=64(-1+i*0)=-64`

The other roots can be obtained by adding 2Pi, 4Pi, and 6Pi to 5Pi. I will work one for you.





(To help you see geometrically, 7Pi/4 falls in the 4th quadrant, 9Pi/4=2Pi+Pi/4 falls in the 1st, and 11Pi/4=2Pi+3Pi/4 fall in the 2nd quadrant)




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