In the explosion of a hydrogen-filled balloon, 0.10g of hydrogen reacted with 0.80g of oxygen. How many grams of water vapor are formed? (Water vapor is the only product.) How do i go about solving this? Thanks!
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Gaseous hydrogen reacts with oxygen to produce water according to the equation:
`2H_2+O_2 rarr 2H_2O`
The number of moles of the reactants are:
according to the reaction stoichiometry,
2 moles of hydrogen require 1 mole of oxygen
so, 0.05 moles of hydrogen require 1*0.05/2, i.e. 0.025 moles of oxygen.
Exactly 0.025 moles of oxygen is present in the reaction mixture.
So, both the reactants would react and exhaust each other out.
From the balanced equation,
2 moles of hydrogen reacts with sufficient oxygen to produce (2*+16), i.e. 18 g H2O
Therefore, 0.05 moles of hydrogen would produce 18*0.05/2, i.e. 0.45 g H2O.
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