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Explain how to factor the following trinomials forms: `x^2 + bx +c` and `ax^2 + bx...
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Use the quadratic formula to factorise the expressions
So if `y = Ax^2+ Bx + C`
the factors satisfy
`x = (-B +- sqrt(B^2 - 4AC))/(2A)`
However, when you factorise `y = Ax^2+ Bx + C`
the term in `x^2` must equal `A`
We can factorise the expression then as
`y = (Ax/h - (A/h)(-B-sqrt(B^2 - 4AC))/(2A))(hx - h(-B+sqrt(B^2 -4AC))/(2A))`
where `h` is any real number (plug in `A=1` to factorise y = x^2 +bx + c) answer
Posted by mathsworkmusic on November 15, 2012 at 3:13 PM (Answer #1)
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