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To solve, expand the integrand by dividing the numerator by the denominator. In doing so, it becomes:
`=int(x - 1 + 2/(x+1) )dx`
`=x^2/2-x+2ln|x+1| + C`
Hence, `int(x^2+1)/(x+1)dx = x^2/2-x+2ln|x+1|+C` .
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