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Evaluate the integral using the fundamental theorem of calculus.y=4x^t + 5x^-1 +...

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betzishor | Student, Grade 11 | (Level 2) Honors

Posted May 3, 2011 at 5:46 AM via web

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Evaluate the integral using the fundamental theorem of calculus.

y=4x^t + 5x^-1 + 6sinx.

 

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giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted May 3, 2011 at 11:03 AM (Answer #2)

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We'll recall the fundamental Theorem of Calculus:

Int f(x)dx = F(b) - F(a) for x = a to x  =b.

Since the limits are not given, we could only calculate the indefinite integral:

Int (4x^t + 5x^-1 + 6sinx)dx

We'll use the additive property of integrals:

Int (4x^t + 5x^-1 + 6sinx)dx = Int 4x^tdx + Int5x^-1dx + Int 6sinxdx

Int ydx  = 4*x^(t+1)/(t+1) + 5 ln|x| - 6cos x + C

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted May 3, 2011 at 12:40 PM (Answer #3)

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We have to find the integral of y=4x^t + 5x^-1 + 6sin x.

I assume t to be a constant.

Int[ y dx]

=> Int[ 4x^t + 5x^-1 + 6sin x dx]

=> Int[4x^t dx] + Int[5x^-1 dx]+ Int [6sin x dx]

=> (4/t+1)*x^(t+ 1) + 5* ln |x| - 6* cos x +C

The required integral is (4/(t+1))*x^(t +1) + 5*ln |x| - 6* cos x +C

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