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Evaluate Integral [upper limit 4, lower limit 1] of 1/sqrt(x) dx

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dcrumpler | (Level 2) eNoter

Posted May 7, 2012 at 10:53 PM via web

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Evaluate Integral [upper limit 4, lower limit 1] of 1/sqrt(x) dx

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thilina-g | College Teacher | (Level 1) Educator

Posted May 7, 2012 at 11:13 PM (Answer #1)

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`y = int_1^4 1/sqrt(x)dx`

`y = int_1^4 x^(-1/2)dx`

`y = intx^(-1/2)dx = x^(1/2)/(1/2) = 2sqrt(x)`

Therefore,

`y = int_1^4 1/sqrt(x)dx = 2(sqrt(4)-sqrt(1)) = 12(2-1) = 2`

`y = int_1^4 1/sqrt(x)dx = 2`

 

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