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Evaluate `int`  1/(z)^1/25 dz Answer=

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elpony | Student, Undergraduate | eNoter

Posted May 8, 2013 at 1:53 AM via web

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Evaluate `int`  1/(z)^1/25 dz


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oldnick | Valedictorian

Posted May 8, 2013 at 2:06 AM (Answer #1)

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`int 1/z^(1/25) dz`


Now  `int x^k dx=1/(k+1) x^(k+1) +c`

So:  `int 1/z^(1/25) dz= int z^(-1/25) dz= 1/(-1/25+1) z^(-1/25+1) +c` `=25/24 z^(24/25)+c`

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ericmilamattim | Honors

Posted June 3, 2013 at 10:25 AM (Answer #4)

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integral 1/z^(1/25) dz
= (25 z^(24/25))/24+C

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