for the equation 4 cos(angle)-sqroot(12)=0 where 0<(angle) greater than or equal to 2(pi), determine the measure of (angle)?

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`4cos(theta)-sqrt(12)=0`

`4cos(theta)=2sqrt(3)`

`cos(theta)=sqrt(3)/2`

theta = `pi/6` or `(11pi)/6`

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