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The empirical formula of a compound is C6H5O, and the molar mass of of the compound is...
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`C = 12g/(mol)`
`H = 1g/(mol)`
`O = 16g/(mol)`
Let us say molecular formula is `(C_6H_5O)_n`
So the weight of `(C_6H_5O)_n` molecule is 280.28g/mol
`(12xx6+1xx5+16xx1)xxn = 280.28`
`(93)xxn = 280.28`
`n = 3.01`
Since n should be a whole number n = 3
so the molecular formula is in the shape of `(C_6H_5O)_3` ` `
so the molecular formula is `C_18H_15O_3`
Posted by jeew-m on January 26, 2013 at 3:12 AM (Answer #1)
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