4x^2+9y^2=36 is equation of a ellipse
Find the equation of the line from the origin to the point x=d (the radial). where x is the first quadrant
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You need to write the standard form of ellipse, hence, you need to divide the equation by 36 such that:
`x^2/9 + y^2/4 = 1`
Hence, the semi-major axis is `a=3` and the semi-minor axis is `b=2` .
You should know that the radial line from origin to the point (a,b) intercepts the ellipse at `(a/sqrt2,b/sqrt2).`
Hence, evaluating the coordinates of point of intersection yields `(3/sqrt2,2/sqrt2).`
You need to write the equation of the radial line such that:
`y - 0 = (2/sqrt2)/(3/sqrt2)(x - 0)`
`y = (2/3)x`
Hence, evaluating the equation of the radial line under given conditions yields `y = (2/3)x` .
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