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Element A combines with element B in the ratio 9:5 by mass. In a different experiment,...

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navpreet14 | Student, Grade 11 | (Level 1) eNoter

Posted November 27, 2012 at 10:24 PM via web

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Element A combines with element B in the ratio 9:5 by mass. In a different experiment, it is found that 1 g of B reacts with 1.8 g of A.

Does this support the law of definite proportions?

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ncchemist | eNotes Employee

Posted November 28, 2012 at 12:57 AM (Answer #1)

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These results do support the law of definite proportions.  We know that A combines with B in a ratio of 9:5 by mass.  If we divide 9 by 5 we get 1.8, so this ratio reduces to 1.8:1.  This corresponds exactly with the second observation that 1.8 g of A reacts with 1.0 g of B, this giving a mass ratio of 1.8:1.  This is the exact same mass ratio as before.  The law of definite proportions states that a compound always exists as set proportions of each element to each other by mass.  Since A and B combine in a constant mass ratio of 1.8:1, these observations uphold the law of definite proportions.

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sanjeetmanna | College Teacher | (Level 3) Assistant Educator

Posted November 28, 2012 at 7:04 AM (Answer #2)

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This Law of Definite Proportion is also known as Law of Constant Composition, This law states that the relative amount of each element in a specific compound is always the same or it can also be defined as a compound always contain the same proportion by mass of its constituent element.

From the question, element A and B combines in the ratio of 9:5 which means 9 grams of A react with 5 grams of B. If 1 gram of B is reacting, then 1.8 grams of A is required which is in the ratio of 9:5. Thus defines the Law of Definite Propotion.

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