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A driver sees a bear in his headlights. He is driving at 25m/s and decelerates at a...
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We can use equations of motion here.
`v^2 = u^2+2aS`
The data we have is:
`u = 25m/s`
`a = -4.9m/s^2` since we have a deceleration
`S = 25m`
`v^2 = 25^2-2xx4.9xx25`
`v = 19.49m/s`
So the speed of ranger after traveling 25m breaking distance is 19.49m/s
Posted by jeew-m on October 7, 2013 at 3:16 AM (Answer #1)
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