A driver sees a bear in his headlights. He is driving at 25m/s and decelerates at a rate of 4.9m/s2.

After breaking for 25.0 m, what is the ranger's speed?

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We can use equations of motion here.

`v^2 = u^2+2aS`

The data we have is:

`u = 25m/s`

`a = -4.9m/s^2` since we have a deceleration

`S = 25m`

`v^2 = 25^2-2xx4.9xx25`

`v = 19.49m/s`

*So the speed of ranger after traveling 25m breaking distance is 19.49m/s*

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