A driver sees a bear in his headlights. He is driving at 25m/s and decelerates at a rate of 4.9m/s2.
After breaking for 25.0 m, what is the ranger's speed?
2 Answers | Add Yours
We can use equations of motion here.
`v^2 = u^2+2aS`
The data we have is:
`u = 25m/s`
`a = -4.9m/s^2` since we have a deceleration
`S = 25m`
`v^2 = 25^2-2xx4.9xx25`
`v = 19.49m/s`
So the speed of ranger after traveling 25m breaking distance is 19.49m/s
V^2- U^2 = 2as
Solving we get,
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes