- Download PDF
If the golfer makes a ten foot putt from point C into the hole (at point D), then how far did the ball travel en route from A to B to C to D? (Hint: use the pythagorean triples 3, 4 , 5; 5, 12, 13; and 8, 15, 17 and the scale of 1 unit=10 feet)
1 Answer | Add Yours
Using the Pythagorean triple 5,12,13, we can determine that the distance from A to B is 13, as the long side is 12 and the short side is 5.
For B to C, the horizontal distance is 16-12=4, and the vertical distance is 8-5=3. This is the Pythagorean triple 3,4,5, therefore the distance from B to C is 5.
C to D is the horizontal distance of 1.
Therefore, the distance it travelled from A to B to C to D is 13+5+1=19. 1 unit = 10 ft; therefore, the ball travelled 19*10=190 ft.
Finally, the distance from the hole to the starting point (D to A) is 17 because the long side from D to A is 15, and the short side is 7, following the Pythagorean triple 8, 15, 17.
We’ve answered 324,484 questions. We can answer yours, too.Ask a question