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A dominant gene (H) produced wire-haired texture in dogs; its recessive allele (h)...

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kathyyyyyy123 | Student, Undergraduate | Honors

Posted March 17, 2013 at 10:51 PM via web

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A dominant gene (H) produced wire-haired texture in dogs; its recessive allele (h) produces smooth hair. A heterozygous female dog is mated with a smooth-haired male dog. What phenotypes are expected in a large number of puppies and in what ratios?

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jerichorayel | College Teacher | (Level 1) Senior Educator

Posted March 18, 2013 at 5:27 AM (Answer #1)

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To solve this problem, let us use the punnett square in order to determine the phenotype rations of the offspring of a heterozygous female dog (Hh) and a recessive male dog (hh). 

The heterozygous female contains a dominant and recessive trait (genotype: Hh) while the smooth-haired male contains only recessive trait (genotype: hh). Doing the punnett square we can have:

      h      h

H    Hh    Hh

h    hh    hh

Results:

2Hh or 50% of the puppies will have a wire-haired texture.

2hh or 50% of the puppies will have a smooth-haired texture.

Sources:

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