Last year I felt an earthquake while I was watching television. The earthquake that I experienced produced a wave that travelled through the earth at a speed of `1.3times10^(-4) m/s` . This wave is incident on a boundary between two types of materials. If this incident angle is `35^o` and the refracted angle is the second medium is `32^o` , what is the speed of the wave in the second medium?

### 1 Answer | Add Yours

According to wave theory, there is a relationship between the angle of incidence of a wave as it encounters the interface between two barriers of differing media and the angle of refraction as it enters into the new media. This relationship is given by

`n1sin(theta)1 = n2sin(theta)2`

` `

`or (n2)/(n1) = (sin(theta1))/(sin(theta2))`

`((n2)/(n1)) = (v1)/(v2)`

So

`v2 = v1 (sin(theta2))/(sin(theta)1)`

`v2 = 1.2times10^(-4) m/s`

` `

**Sources:**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes