Divide. `(x^3+2x^2-3x+2)/(x+1)`

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To divide, perform long division.

          `x^2``+` `x` `-` `4`      

 `x+1 ` `|``bar( x^3 + 2x^2-3x+2)`

    `(-)` `x^3+x^2`

         `------------`

                  `x^2 -3x + 2`

        `(-)`     `x^2+x`

        `------------`      

                      `-4x+ 2`

             `(-)`   `-4x - 4`

        `------------`

                               `6`

Hence, `(x^3+2x^2-3x+2)/(x+1)= x^2+x-4+6/(x+1)` .

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