Discrete Math proof help please!
I have to prove : if k ≡ l mod j and f ≡ g mod j then (k+f) ≡ (l+g) mod jI'm using direct proof to prove this.
let's say s and t are integers...
Would l = k + sj, and g = f + tj?
If so, can you please help me out how to prove (k+f) ≡ (l+g) mod j. The mod is killing me! :(
1 Answer | Add Yours
so l+g = k +sj + f + tj = (k+f) + (s+t)j = (k+f) mod j
We’ve answered 331,117 questions. We can answer yours, too.Ask a question