A disc is radial crossed, through sliding contacts, by an electrical current I=4A. The disc is set perpendicullar on a magnetic field, B=20mT.
The disc radius R=50mm
1. Calculate the power of engine, knowing the speed is n=5rot/s.
2. Find the torque moment.
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We'll take an infinitesimal element"dx", of radial current. This element is placed at the distance "x" from the axis of the disc.The elementary force which is acting on the current segment:
The power developed by this force is:
If we'll inegrate the relation above:
P=Integral (dP)=Integral(l*B*2*pi*n*x*dx) =
=l*B*2*pi*n*(x^2/2) from 0 to R=pi*n*R^2*I*B=3.14mW
The elementary moment of the elementary force dF is:
M=Integral (dM)=I*B*Integral (x*dx) from 0 to R=
The result could be obtained from the relation P=M*omega
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