derivative of xcos2x is =?
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Let y = x*cos2x
We'll apply the chain rule and also the product rule.
dy/dx = [d/dx(x)]* cos2x + x* [d/dx (cos 2x)]
We'll apply the chain rule for the term:
[d/dx (cos 2x)] = -sin 2x* (2x)'
[d/dx (cos 2x)] = -2sin 2x
The differentiated given function is: dy/dx = cos 2x - 2x(sin 2x)
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