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Differentiate the function: `y=ln(4*sin^2x)`

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sllysmith | Student, Undergraduate | (Level 2) eNoter

Posted March 8, 2012 at 1:37 PM via web

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Differentiate the function: `y=ln(4*sin^2x)`

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted March 8, 2012 at 1:56 PM (Answer #1)

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The function y =` ln(4*sin^2x)` has to be differentiated. Use the chain rule.

y' = `(1/(4*sin^2x))*4*2*sin x*cos x`

=> y' = `(1/(sin x))*2*cos x`

=> y' = `2*cot x`

The required derivative is y' = 2*cot x

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