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The equation of the circle is `x^2+y^2=30` .
Then the inequality for the interior (the disk) is `x^2+y^2<30` and the inequality for the exterior is `x^2+y^2>30` .
Substitute x=5 and y=2 to get 29<30.
The point lies in the interior.
Equatio f the given circle is
cetre of circle (0,0)
radius of circle= sqrt(30)
distance d between (0,0) and point (5,2)
since d is less than radius of the circle So point will inside the circle.
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