Determine whether the equation defines y as a function of x.

`7x^2+3y^2=1`

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First we will have to isolate y on the left side.

`==gt 7x^2 + 3y^2 = 1`

` ==gt 3y^2 = 1- 7x^2 `

`==gt y^2 = (1-7x^2)/3 `

`==gt y= +- (1-7x^2)/3`

`` Now we notice that we have two possible values to y for each value of x.

Therefore, we have two images for the value of x ( positive value and negative value.

For example, if x= 1 ==> y= 2 and y= -2)

Then, y is **NOT** a function of x.

Or, we can graph y and test the vertical line.

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