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Determine the value of a and b if 3a + 2i = (3 + 4bi)^2
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The value of a and b has to be determined given that 3a + 2i = (3 + 4bi)^2
3a + 2i = (3 + 4bi)^2
=> 3a + 2i = 9 - 16b^2 + 24bi
equate the real and complex coefficients
=> 9 - 16b^2 = 3a and 2 = 24b
=> b = 1/12
3a = 9 - 16/144 = 80/9
=> a = 80/27
The value of a = 80/27 and b = 1/12
Posted by justaguide on April 1, 2013 at 6:10 PM (Answer #1)
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