Determine the solution set using the graphical method x^2+y^2>4 (i) (x-2)^2+y^2<4 (ii)Show complete solution and explain the answer.



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Posted on (Answer #1)

The graph of `x^2+y^2=4` is a circle with a center at (0,0) and radius 2.  To represent `x^2+y^2>4` the circle will be dashed and the outside of the circle is shaded.

To represent `(x-2)^2+y^2<4` the circle has a center at (2,0) and radius 2.  The circle will be dashed and shaded on the inside.

The solution set is represented by the intersection of the two shadings.  It is the circle on the right, not including where the two circles intersect.


I'm unable to graph with shading, but I hope you can see the solution looking like a pac man figure facing left.


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